Question

1целая 2/3 × 6 - 1целая 23/42 × 3целую 1/13 + 2целых 1/8 × 1целую 29/51=

Answer 1

Решить пример.

$1dfrac{2}{3} * 6 - 1dfrac{23}{42} * 3dfrac{1}{13} + 2dfrac{1}{8} * 1dfrac{29}{51} = dfrac{5*6}{3} - dfrac{65*40}{42*13} + dfrac{17*80}{8*51} =\= 10 - dfrac{5*20}{21} + dfrac{10}{3} = 10- dfrac{100}{21} + dfrac{10}{3} = 10 - dfrac{100 - 10*7}{21} =\= 10 - dfrac{100 - 70}{21} = 10 - dfrac{30}{21} = 10 - 1dfrac{9}{21} = 8dfrac{12}{21} = 8dfrac{4}{7}.$

Ответ: $8dfrac{4}{7}.$