Question

16-4x² = 9a²-25b²


= (2a-3b)(2a+3b) (1-a)² = (6a+ 4c)² Q =


(16+4x)(16-4x) (3a+25b)(3a+25b) =




2a²-3b² (1−b)(1+b) 36a² +24ab+16b​

Answer 1

Ответ:1) (4a² - y)(y + 4a²)  = 4a²y + 16a⁴ - y² - 4a²y = 16a⁴ - y²;

2) (0,3b³ + х)(0,3b³ - x) = 0,09b⁶ - 0,3b³x + 0,3b³x - x² = 0,09b⁶ - x²;

3) (1,1c² + z²)(z² - 1,1c²) = 1,1c²z² - 1,21c⁴ + z⁴ - 1,1c²z² = z⁴ - 1,21c⁴;

4) (21d² - k³)•(21d² + k³) = 441d⁴ + 21d²k³ - 21d²k³ - k⁶ = 441d⁴ - k⁶;

5) (5a³ - 4b²)(4b² + 5a³) = 20a³b² + 25a⁶ - 16b⁴ - 20a³b² = 25a⁶ - 16b⁴;

6) (1,9c⁴ + 6d)(6d - 1,9c⁴) = 11,4c⁴d - 3,61c⁸ + 36d² - 11,4c⁴d =

= 36d² - 3,61c⁸

Объяснение: