Question

1342. Спасите кто нибудь ​

Answer 1

$displaystyle left { {{dfrac{3x - 1}{2} + dfrac{9 - 5y}{3} = 2,5 | cdot 6 } atop {dfrac{8 - 3y}{4} - dfrac{6 + 5x}{3} = 0 | cdot 12 }} right.$

$displaystyle left { {{3(3x - 1) + 2(9 - 5y) = 15} atop {3(8 - 3y) - 4(6 + 5x) = 0 }} right.$

$displaystyle left { {{9x - 3 + 18 - 10y = 15} atop {24 - 9y - 24 - 20x = 0}} right.$

$displaystyle left { {{9x - 10y = 0 | cdot 20} atop {-20x - 9y = 0 | cdot 9 }} right.$

$+ displaystyle left { {{180x - 200 y = 0} atop {-180x - 81y = 0}} right.$

$-281y = 0\y = 0$

$9x - 10 cdot 0 = 0\x = 0$

Ответ: (0; 0).