Question

12-(4-х) в квадрате =х (3-х)

Answer 1

12-(4-х)²=х(3-х)
12-(16-8x+x²)=3x-x²
12-16+8x-x²=3x-x²
12-16= -8x+x²+3x-x²
4= -5x
x= 4/(-5)
x= -0.8