Question

-11x2 + 3x + 14.



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Answer 1

$-11x^2+3x+14=0\\11x^2-3x-14=0\\D=(-3)^2-4 \cdot 11 \cdot (-14)=9+44 \cdot 14 = 625\\\sqrt{D}=25\\x_1=\dfrac{3+25}{2 \cdot 11}=\dfrac{28}{22}=\dfrac{14}{11}\\x_2=\dfrac{3-25}{22}=\dfrac{-22}{22}=-1.$