Question

(10-8x)^4+8(8x-10)^2-9=0
Решите пожалуйста!

Answer 1

$(10-8x)^4+8(8x-10)^2-9=0 \ (8x - 10)^4+8(8x-10)^2-9=0 \ y =( 8x - 10) ^{2} geqslant 0 \ {y}^{2} + 8y - 9 = 0 \ (y - 9)(y + 1) = 0 \ y1 =9 \ ( 8x - 10) ^{2} = 9 \ 4(4x - 5) ^{2} = 9 \ 4x - 5 = ±frac{3}{2} \ 4x = 5±1.5 \ x1 =6.5 div 4 \ x1 = 1.625 \x2 = 3.5 div 4 \ x2 = 0.875\ \ \ y2 < 0$
ответ
$\ x1 = 1.625 \ x2 = 0.875$