Question

1) (x-3)= -(а + 1) = 12
2) (3x-2) - (1 - 3x)(3х + 2) = 36​

Answer 1

1) x-3=12     x=15

-(a+1)=12     a= -13

(a, x) = (-13, 15)

15-3= -(-13+1)=12

2) 3x-2-(3x+2-9$x^{2}$-6x)=36

3x-2-(-3x+2-9$x^{2}$)=36

3x-2+3x-2+9$x^{2}$=36

6x-4+9$x^{2}$-36=0

9$x^{2}$+6x-40=0

D=$\sqrt{6^{2} -4*9*(-40)}$=1476=6$\sqrt{41}$

x1= $\frac{-6+6\sqrt{41} }{18}$=$\frac{-1+\sqrt{41} }{3}$

x2= $\frac{-6-6\sqrt{41} }{18}$=$\frac{-1-\sqrt{41} }{3}$