Question

1) (x-2)-(2x+3)
2) 2(3m-4n)+4(5m-8n)
3) y(y+3)-(y в квадрате+y-6)
Помогите дам 25 баллов

Answer 1

$1) : (x - 2) - (2x + 3) = x - 2 - 2x - 3 = - x -5$
$2) : 2(3m - 4n) + 4(5m - 8n) = 6m - 8n + 20m - 32n = 26m - 40n$

$3) : y(y + 3) - ( {y}^{2} + y - 6) = {y}^{2} + 3y - {y }^{2} - y + 6 = 2y + 6$