Question

1 вариант помогите.​

Answer 1

Ответ:

$a)\;\;2\sqrt{9}-\sqrt{64} =6-8=-2\\\\b)\;\;\sqrt{3\frac{1}{16}}=\sqrt{\frac{49}{16}}=\frac{7}{4} \\\\c)\;\;4*\sqrt{0.25} =4*0.5=2\\\\\\a)\;\;\sqrt{2500*49}=50*7 = 350\\\\b)\;\;\sqrt{3}*\sqrt{48}=\sqrt{144}=12\\\\c)\;\;\frac{\sqrt{24}}{\sqrt{6}} =\sqrt{4} =2\\\\d)\;\;\sqrt{5^4} =5^2=25\\\\\\a) x^2=0.25\\\\x=0.5\\\\c)\;\;4+\sqrt{x}=17\\\\\sqrt{x}=13\\\\x=169$