Question

 1)$\sqrt{9-4 \sqrt{5} } + \sqrt{14 - 6 \sqrt{5} }$
2)$\sqrt{11-4 \sqrt{7} } + \sqrt{16- 6 \sqrt{7} }$


помогите срочно

Answer 1

$1)\sqrt{9-4\sqrt{5}}+\sqrt{14-6\sqrt{5}}=\sqrt{(\sqrt{5}-2)^2}+\sqrt{2(7-3\sqrt{5})}=$
$=\sqrt{5}-2+\sqrt{9-6\sqrt{5}+5}=\sqrt{5}-2+\sqrt{(3-\sqrt{5})^2}=$
$=\sqrt{5}-2+3-\sqrt{5}=1$

$2)\sqrt{11-4\sqrt{7}}+\sqrt{16-6\sqrt{7}}=\sqrt{(\sqrt{7}-2)^2}+\sqrt{2(8-3\sqrt{7})}=$
$=\sqrt{7}-2+\sqrt{(3-\sqrt{7})^2}=\sqrt{7}-2+3-\sqrt{7}=1$