Question

1) $2^{2 + log_{2}5}$

2) $5^{log_{5}16-1}$

Answer 1

$2^{2+log_{2}5}=2^2*2^{log_{2}5}=4*5=20\ 5^{log_{5}16-1}= frac{5^{log_{5}16}}{5}=frac{16}{5}$