Question

1 и 2 задание, срочно!!!!​

Answer 1

Ответ:

Объяснение:

$\frac{a^3b}{c^5} \frac{c^4}{a^2b} =\frac{a}{c}$

$\frac{100-y&2}{21xy} \frac{28y^2}{y^2+20y+100} = \frac{4y(10-y)}{3x(10+y)}$

$\frac{(a+b)^2}{a^3+a^2b} \frac{ab^2+b^3}{4a+4b} = \frac{b^2(a+b)}{4a^2}$

$\frac{a^2b^4}{m^3} : \frac{a^3b^2}{m^2} =\frac{a^2b^4}{m^3} \frac{m^2}{a^3b^2} = \frac{b^2}{am}$

$\frac{a^2-ab}{a^2+ab} :\frac{9a-9b}{10(a-b)} =\frac{10}{9}$

$\frac{36b^2c}{a^2+14a+49}:\frac{18bc^2}{a^2-49} =\frac{7(a-7)}{3(a+7)}$