Question

1) 7x – 4 = x – 16

2) 13 – 5x = 8 – 2x

3) 1,3p – 11 = 0,8p + 5

4) 0,71x – 13 = 10 – 0,29x

5) 3,1(1 – 3t) + t = 0,4(t – 14)

6) 2 = (3x – 5) – (7 – 4x)

Answer 1

Ответ:

1) 7x-4=x-16

7x-x=-16+4

6x=-12

x=-2

2) 13-5x=8-2x 

-5x+2x=8-13

-3x=-5

x=5/3

3) 1,3p-11=0,8p+5

1,3p-0,8p=5+11

0,5p=16

p=32

 

4) 0,71x-13=10-0,29x

0,71x+0,29x=10+13

x=23

5) 3,1(1 – 3t) + t = 0,4(t – 14)

3,1-9,3t+t=0,4t-5,6

-9,3t+t-0,4t=-5,6-3,1

-8,7t=-8,7

t=1

6)2 = (3x – 5) – (7 – 4x)

3x-5-7+4x=2

7x-12=2

7x=14

x=2