1/6 + (x-3)//4-8x=(x+1)//(2x-1) - (11x-5)//(24x-12)
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Ответил Yena
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ОДЗ 2x-1≠0 x≠0,5
![frac{1}{6}+frac{x-3}{4-8x}=frac{x+1}{2x-1}-frac{11x-5}{24x-12} \
frac{1}{6}+frac{x-3}{4(1-2x)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \
frac{1}{6}-frac{x-3}{4(2x-1)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \
frac{2-3(x-3)}{12(2x-1)}=frac{12(x+1)-(11x-5)}{12(2x-1)} \
2-3x+9=12x+12-11x+5 \ -3x+11=x+17 \ -4x=6 \ x=-1,5](https://tex.z-dn.net/?f=frac%7B1%7D%7B6%7D%2Bfrac%7Bx-3%7D%7B4-8x%7D%3Dfrac%7Bx%2B1%7D%7B2x-1%7D-frac%7B11x-5%7D%7B24x-12%7D+%5C+%0Afrac%7B1%7D%7B6%7D%2Bfrac%7Bx-3%7D%7B4%281-2x%29%7D%3Dfrac%7Bx%2B1%7D%7B2x-1%7D-frac%7B11x-5%7D%7B12%282x-1%29%7D++%5C+%0Afrac%7B1%7D%7B6%7D-frac%7Bx-3%7D%7B4%282x-1%29%7D%3Dfrac%7Bx%2B1%7D%7B2x-1%7D-frac%7B11x-5%7D%7B12%282x-1%29%7D++%5C+%0Afrac%7B2-3%28x-3%29%7D%7B12%282x-1%29%7D%3Dfrac%7B12%28x%2B1%29-%2811x-5%29%7D%7B12%282x-1%29%7D++%5C%0A2-3x%2B9%3D12x%2B12-11x%2B5+%5C++-3x%2B11%3Dx%2B17+%5C+-4x%3D6+%5C+x%3D-1%2C5+ "frac{1}{6}+frac{x-3}{4-8x}=frac{x+1}{2x-1}-frac{11x-5}{24x-12} \
frac{1}{6}+frac{x-3}{4(1-2x)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \
frac{1}{6}-frac{x-3}{4(2x-1)}=frac{x+1}{2x-1}-frac{11x-5}{12(2x-1)} \
frac{2-3(x-3)}{12(2x-1)}=frac{12(x+1)-(11x-5)}{12(2x-1)} \
2-3x+9=12x+12-11x+5 \ -3x+11=x+17 \ -4x=6 \ x=-1,5")
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