Question

1)4x-x³=0
2)-20x²+5x⁴=0
3)4x³-3x²=4x-3
Помогите если можно то с обеспечением

Answer 1

$1)4x - {x}^{3} = 0 \ x times (4 - {x}^{2} ) = 0 \ x = 0 \ 4 - {x}^{2} = 0 \ x = 0 \ x = - 2 \ x = 2 \ x1 = - 2 \ x2 = 0 \ x3 = 2$
$3)4 {x}^{3} - 3 {x}^{2} = 4x - 3 \ {x}^{2} times (4x - 3) = 4x - 3 \ {x}^{2} times (4x - 3) - (4x - 3) = 0 \ (4x - 3) times ( {x}^{2} - 1) = 0 \ 4x - 3 = 0 \ {x}^{2} - 1 = 0\ x1 = - 1 \ x2 = 0.75 \ x3 = 1$

$2) - 20 {x}^{2} + 5 {x}^{4} = 0 \ - 5 {x}^{2} times (4 - {x}^{2} ) = 0 \ {x}^{2} times (4 - {x}^{2} ) = 0 \ {x}^{2} = 0 \ 4 - {x}^{2} = 0 \ x1 = - 2 \ x2 = 0 \ x3 = 2$