Question

(1/3)^-4 * 3^-2 + 1/12 * 3^2

Answer 1

$( frac{1}{3} )^{-4}*3^{-2}+ frac{1}{12} *3^2=3^4*3^{-2}+ frac{1}{12} *3^2=(3^2*3^{-2}+ frac{1}{12} )*3^2=$
$=(3^0+ frac{1}{12} )*9=(1+ frac{11}{12} )*9= frac{12+1}{12} *9= frac{13}{12}*9= frac{13}{14} *3= frac{39}{4} =$
$=9 frac{3}{4} =9,75$