Question

1 . ( 3 - 2х ) ( 8х + 1 ) + ( 4х - 1 )² =
2 . ( 9х + 10 ) ( 9х - 10 ) - ( 7х + 2 )² + 16 ( 7 - 2х² ) =
3 . [( 6х - 1 )² - ( 8х + 1 )²] : ( - 28х ) =
4. ( 4 - х ) ( 4 + х ) - ( 15х³ - 3х² ) : 3х² + ( х + 3 )²

Заранее спасибо

Answer 1

1)
$(3 - 2x)(8x + 1) + (4x - 1) \ (4x - 1) = \ = 24x - 16x {}^{2} + 3 - 2x + 16x {}^{2} - \ - 4x - 4x + 1 = \ = 14x + 4 = \ = 2(7x + 2)$

2)
$(9x + 10)(9x - 10) - (7x + 2) \ (7x + 2) + 16(7 - 2x {}^{2} ) = \ = 81x {}^{2} - 100 - 49x {}^{2} - 28x - 4 + \ + 112 - 32x {}^{2} = \ = 8 - 28x = \ = 4(2 - 7x)$

3)
$((6x - 1)(6x - 1) - (8x + 1) \ (8x + 1)) div ( - 28x) = \ = (36x {}^{2} - 12x + 1 - 64x {}^{2} - 16x - \ - 1) div ( - 28x) = \ = ( - 28x {}^{2} - 28x) div ( - 28x) = \ = ( - 28x {}^{2} - 28x) times ( - frac{1}{28} x) = \ \ = x {}^{3} + x {}^{2} = \ = x {}^{2} (x + 1)$

4)
$(4 - x)(4 + x) - (15x {}^{3} - 3x {}^{2} ) times \ times frac{1}{3 } x {}^{2} + (x + 3)(x + 3) = \ \ = 16 - x {}^{2} - 5x {}^{5} + x {}^{4} + x {}^{2} + 6x + \ + 9 = \ = 25 - 5x {}^{5} + x {}^{4} + 6x$