Question

1,2, пожалуйста.,..,.,.,..,

Answer 1

1. $AB = sqrt{16+16} = sqrt{32}$.

$AB=DB=frac{sqrt{32} }{2} =frac{sqrt{32} }{sqrt{4}}=sqrt{frac{32}{4} } =sqrt{8}$.

$CD=sqrt{16-8} =sqrt{8}$.

$MC=sqrt{9-8} =sqrt{1} =1$.

2.$AD=DB=frac{1}{2} AB=frac{2sqrt{3} }{2} =sqrt{3} .$

$DC=sqrt{12-3} =sqrt{9} =3.$

$MC=sqrt{16+9} =sqrt{25} =5.$

Answer 2

Спасибо большое!