1)2(х-1)=3(2х-1);
2)3(1-x)=4x-11;
3)3-5(x-1)=x-2;
4)3(x-2)-2(x-1)=17.
как решить?
Ответы на вопрос
Ответил Аноним
0
1)
2X - 2 = 6X - 3
6X - 2X = - 2 + 3
4X = 1
X = 0,25
2)
3 - 3X = 4X - 11
4X + 3X = 3 + 11
7X = 14
X = 2
3)
3 - 5X + 5 = X - 2
X + 5X = 8 + 2
6X = 10
X = 10/6 = 5/3 = 1 2/3
4)
3X - 6 - 2X + 2 = 17
X = 17 + 4
X = 21
2X - 2 = 6X - 3
6X - 2X = - 2 + 3
4X = 1
X = 0,25
2)
3 - 3X = 4X - 11
4X + 3X = 3 + 11
7X = 14
X = 2
3)
3 - 5X + 5 = X - 2
X + 5X = 8 + 2
6X = 10
X = 10/6 = 5/3 = 1 2/3
4)
3X - 6 - 2X + 2 = 17
X = 17 + 4
X = 21
Ответил mironova2001
0
Спасибо
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